$\frac{29.095}{2.3}$
$\lim\:_{x\to\:2}\left(\frac{x^2-4x+4}{x^2+x-6}\right)$
$f\left(x\right)=\frac{\left(3-2x\right)}{\left(x^2-3x+2\right)}$
$\frac{1}{1+4x+4x^2}$
$1b$
$-2x<16$
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