$\frac{1}{\tan}=\cot$
$\frac{1}{16}-\frac{4x^2}{49}$
$\frac{x^2+8}{3}=16$
$\int\sqrt[2]{x^3+3}\:x^5dx$
$\left(+75\right)\:-\:\left(-39\right)$
$\lim_{n\to infinity}\left(\frac{0.75e^{\frac{t}{n}}}{1-0.25e^{\frac{t}{n}}}\right)^n$
$4,834+0.456$
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