Exercise
$\int\:\frac{5x+7}{x^2-4x+3}dx$
Step-by-step Solution
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((5x+7)/(x^2-4x+3))dx. Rewrite the expression \frac{5x+7}{x^2-4x+3} inside the integral in factored form. Rewrite the fraction \frac{5x+7}{\left(x-1\right)\left(x-3\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{-6}{x-1}+\frac{11}{x-3}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{-6}{x-1}dx results in: -6\ln\left(x-1\right).
Find the integral int((5x+7)/(x^2-4x+3))dx
Final answer to the exercise
$-6\ln\left|x-1\right|+11\ln\left|x-3\right|+C_0$