Exercise
$\int\frac{-3x^2+2}{x^3+4x^2}dx$
Step-by-step Solution
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((-3x^2+2)/(x^3+4x^2))dx. Rewrite the expression \frac{-3x^2+2}{x^3+4x^2} inside the integral in factored form. Rewrite the fraction \frac{-3x^2+2}{x^2\left(x+4\right)} in 3 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{1}{2x^2}+\frac{-23}{8\left(x+4\right)}+\frac{-1}{8x}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{1}{2x^2}dx results in: \frac{1}{-2x}.
Find the integral int((-3x^2+2)/(x^3+4x^2))dx
Final answer to the exercise
$\frac{1}{-2x}-\frac{23}{8}\ln\left|x+4\right|-\frac{1}{8}\ln\left|x\right|+C_0$