$y'=\frac{1}{e^x}\cdot y$
$1x^7y$
$\frac{1+\cos\theta}{\sin^{2}\theta}=\frac{1}{1-\cos\theta}$
$\sqrt{1-8x^2}y'=x$
$-14+21-\left(-5\right)$
$\int x\left(6x^2-4x+5\right)dx$
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