$4\left(2x^2+4x\right)+x^2$
$\int\frac{3x^2+3x+4}{4x^2-4}dx$
$\left(3x^2+2y^3-1\right)^2$
$\frac{d}{dx}\left(x^3-y^5+3x^2-6y=0\right)$
$25x^2+120x+144=0$
$5\left(3\right)^2-3\left(3\right)\left(-2\right)-4\left(4\right)$
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