$\int\left(\frac{e^u}{\left(9-e^u\right)^2}\right)du$
$\left(-5x^2\right)\left(-4x^3\right)$
$\lim\:_{x\to\:0}\left(\frac{cosx-1}{\:x}\right)$
$\left(w^6\right)^{\frac{1}{4}}$
$-4x^2+16x+20+9y^2=0$
$\cos10\cdot\left(\tan10+1\right)$
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