Exercise
$\int\frac{2x-3}{\left(x+4\right)\left(x-1\right)\left(x+1\right)}dx$
Step-by-step Solution
Learn how to solve problems step by step online. Find the integral int((2x-3)/((x+4)(x-1)(x+1)))dx. Rewrite the fraction \frac{2x-3}{\left(x+4\right)\left(x-1\right)\left(x+1\right)} in 3 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{-11}{15\left(x+4\right)}+\frac{-1}{10\left(x-1\right)}+\frac{5}{6\left(x+1\right)}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{-11}{15\left(x+4\right)}dx results in: -\frac{11}{15}\ln\left(x+4\right). The integral \int\frac{-1}{10\left(x-1\right)}dx results in: -\frac{1}{10}\ln\left(x-1\right).
Find the integral int((2x-3)/((x+4)(x-1)(x+1)))dx
Final answer to the exercise
$-\frac{11}{15}\ln\left|x+4\right|-\frac{1}{10}\ln\left|x-1\right|+\frac{5}{6}\ln\left|x+1\right|+C_0$