Exercise
$\int\frac{2x-5}{x^2-4x+4}dx$
Step-by-step Solution
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((2x-5)/(x^2-4x+4))dx. Rewrite the expression \frac{2x-5}{x^2-4x+4} inside the integral in factored form. Rewrite the fraction \frac{2x-5}{\left(x-2\right)^{2}} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{2}{x-2}+\frac{-1}{\left(x-2\right)^{2}}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{2}{x-2}dx results in: 2\ln\left(x-2\right).
Find the integral int((2x-5)/(x^2-4x+4))dx
Final answer to the exercise
$2\ln\left|x-2\right|+\frac{1}{x-2}+C_0$