$2x^2-12x-1$
$-5\cdot4-3$
$.60=\frac{e}{440}$
$\frac{\left(3x^3\right)}{\left(x-5\right)^2}$
$\lim_{x\to-2}\frac{x^2-4x+8}{2-x}$
$\frac{4^7}{4^2}$
$\int\left(\frac{6}{\left(3x-5\right)^4}\right)dx$
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