$\int_4^5\left(\frac{x^3+4x}{x^4+8x^2+4}\right)dx$
$\frac{6-2x}{3}<1$
$6a-4=3a+5$
$\frac{1}{x^2}+\frac{1}{x^4}$
$24-12x+6x^2-3x^3$
$4^2-4^3$
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