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- Integrate by partial fractions
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- Integrate using tabular integration
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- Weierstrass Substitution
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- Integrate using basic integrals
- Product of Binomials with Common Term
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Rewrite the expression $\frac{6x}{x^3-8}$ inside the integral in factored form
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$\int\frac{6x}{\left(x-2\right)\left(x^2+2x+4\right)}dx$
Learn how to solve problems step by step online. Find the integral int((6x)/(x^3-8))dx. Rewrite the expression \frac{6x}{x^3-8} inside the integral in factored form. Take out the constant 6 from the integral. Rewrite the fraction \frac{x}{\left(x-2\right)\left(x^2+2x+4\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{1}{6\left(x-2\right)}+\frac{-\frac{1}{6}x+\frac{1}{3}}{x^2+2x+4}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately.
