$\frac{x^4-4^4}{x-4}$
$3a^3b^3a^2b^3$
$\left(2x^{n+1}+3x^{n+2}\right)^2$
$\left(5\:tan\:x\:+7\right)\left(tan\:x-1\right)=0$
$\int\frac{x^2}{x^4-2x^2-81}dx$
$\frac{x-5}{8}=\frac{x}{16}$
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