$\int3\left(x^2-4\right)\left(x^3-12x\right)^4dx$
$\int_{1.8}^{2.4}\:x\:e\:^{-x}dx$
$\left(3a+2b\right)\cdot\left(4ab+3b\right)$
$40+40+2$
$-4-\left(-\frac{25}{5}\right)+2-\frac{15}{3}$
$x\left(2x-9\right)$
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