$93+46$
$\frac{dy}{dx}=\frac{1}{2x^3}$
$\frac{x^3+8}{x^2+4}$
$\left(121x^2-144m^2\right)$
$3+6x+9$
$7\left(3+5\right)$
$\frac{\left(tan\:alpha\:+\:tan\:beta\right)}{cot\:alpha\:+\:cot\:beta}$
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