$\int\left(\sqrt{x}-3\right)\left(\sqrt{x}+1\right)^{-1}dx$
$\sqrt{x+2-3}$
$x^2\:+\:26x\:+\:25$
$2x-6+4x$
$\left(8^2\right)^3$
$\frac{300}{10}$
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