∫te14tdt\int te^{14t}dt∫te14tdt
b18=18\frac{b}{18}=1818b=18
dydx=x1−y2+y\frac{dy}{dx}=\frac{x}{\sqrt{1-y^2}+y}dxdy=1−y2+yx
∫(−2z35−5z83)dz\int\left(\frac{-2z}{3}\sqrt{5-\frac{5z}{8}}^3\right)dz∫(3−2z5−85z3)dz
(2y−3y)\left(2y-3y\right)(2y−3y)
cosθ secθ −tanθ \frac{cos\theta\:}{sec\theta\:-tan\theta\:}secθ−tanθcosθ
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