$\frac{sin\:a}{1+cos\:a}=\frac{1-cosa}{sina}$
$\frac{d}{dx}\ln\sqrt[3]{x^3+8}$
$\left(_-10\right)+\left(-12\right)+\left(-30\right)+\left(-6\right)+\left(-14\right)+\left(-20\right)$
$x+13=4x+34$
$\left|2+3\left(-4\right)\right|$
$\left(8a^3-64x^3y^3\right)$
$\left(3x+2y\right)\left(3-2y\right)$
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