$3\frac{1}{3}$
$\frac{x^3+5x}{\left(2x-1\right)^2\left(x^2+3\right)}$
$\left(1-3x-2x^2+6x^3\right)$
$\frac{6x-36}{5x^2-180}$
$\frac{2}{x+1}-5\ge0$
$\left(-50\right)\:\left(-5\right)$
$\frac{10^{30}}{10^{12}}$
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