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f(x)=sin(x)^4(2+tan(x)^2)cos(x)^3−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫sin⁡(x)4(2+tan2x)cos3xdx\int\sin\left(x\right)^4\left(2+tan^2x\right)cos^3xdx

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Final answer to the exercise

27cos⁡(x)2sin⁡(x)+47sin⁡(x)+−6cos⁡(x)4sin⁡(x)35−835cos⁡(x)2sin⁡(x)−1635sin⁡(x)+−2sin⁡(x)3cos⁡(x)47+sin⁡(x)77+C0\frac{2}{7}\cos\left(x\right)^{2}\sin\left(x\right)+\frac{4}{7}\sin\left(x\right)+\frac{-6\cos\left(x\right)^{4}\sin\left(x\right)}{35}-\frac{8}{35}\cos\left(x\right)^{2}\sin\left(x\right)-\frac{16}{35}\sin\left(x\right)+\frac{-2\sin\left(x\right)^{3}\cos\left(x\right)^{4}}{7}+\frac{\sin\left(x\right)^{7}}{7}+C_0

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∫sin(x)4(2+tan2x)cos3xdx
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