∫∞0(4e5x)dx\int_{\infty}^0\left(4e^{5x}\right)dx∫∞0(4e5x)dx
limx→02x−14x−1\lim_{x\to0}\frac{2^x-1}{4^x-1}x→0lim4x−12x−1
−1−y-1-y−1−y
4r−1=354r-1=354r−1=35
a4−16=0a^4-16=0a4−16=0
2+10−3⋅72+10-3\cdot72+10−3⋅7
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