Multiply and divide by the conjugate of
Multiplying the fraction by $\sqrt{1+\cos\left(x\right)}$
Apply the property of power of a product in reverse: $a^n\cdot b^n=(a\cdot b)^n$
Multiply the single term $1+\cos\left(x\right)$ by each term of the polynomial $\left(1-\cos\left(x\right)\right)$
Solve the product $-\cos\left(x\right)\left(1+\cos\left(x\right)\right)$
Multiply the single term $\cos\left(x\right)$ by each term of the polynomial $\left(-1-\cos\left(x\right)\right)$
Simplifying
Simplify the expression
We can solve the integral $\int\frac{\sin\left(x\right)}{\sqrt{1-\cos\left(x\right)}}dx$ by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it $u$), which when substituted makes the integral easier. We see that $\sqrt{1-\cos\left(x\right)}$ it's a good candidate for substitution. Let's define a variable $u$ and assign it to the choosen part
Now, in order to rewrite $dx$ in terms of $du$, we need to find the derivative of $u$. We need to calculate $du$, we can do that by finding the derivative of the equation above
Isolate $dx$ in the previous equation
Substituting $u$ and $dx$ in the integral and simplify
The integral of a constant is equal to the constant times the integral's variable
Replace $u$ with the value that we assigned to it in the beginning: $\sqrt{1-\cos\left(x\right)}$
As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$
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