Final answer to the problem
$-\frac{1}{8}\cos\left(4x\right)+C_0$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using trigonometric identities
- Integrate using basic integrals
- Product of Binomials with Common Term
- Load more...
Can't find a method? Tell us so we can add it.
1
Simplify $\cos\left(2x\right)\sin\left(2x\right)$ into $\frac{\sin\left(4x\right)}{2}$ by applying trigonometric identities
$\int\frac{\sin\left(4x\right)}{2}dx$
Learn how to solve differential equations problems step by step online.
$\int\frac{\sin\left(4x\right)}{2}dx$
Learn how to solve differential equations problems step by step online. Solve the trigonometric integral int(cos(2x)sin(2x))dx. Simplify \cos\left(2x\right)\sin\left(2x\right) into \frac{\sin\left(4x\right)}{2} by applying trigonometric identities. Take the constant \frac{1}{2} out of the integral. Apply the formula: \int\sin\left(ax\right)dx=-\left(\frac{1}{a}\right)\cos\left(ax\right)+C, where a=4. Simplify the expression.
Final answer to the problem
$-\frac{1}{8}\cos\left(4x\right)+C_0$
