$\left(-21\cdot\:1668\right)$
$\sqrt[3]{32x^4}y^2$
$\lim_{x\to0}\left(\frac{\left(x^2-36\right)\left(x-6\right)}{x^2-12x+36}\right)$
$8-3c=8+2c$
$20x^3+30x^4-40x^6-50x^5$
$f\left(x\right)=\left(x^{\frac{2}{5}}+12\right)^2$
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