Exercise
$\int e^{-y^2}dy$
Step-by-step Solution
Learn how to solve polynomial factorization problems step by step online. Find the integral int(e^(-y^2))dy. Rewrite the function e^{-y^2} as it's representation in Maclaurin series expansion. The power of a product is equal to the product of it's factors raised to the same power. Simplify \left(y^2\right)^n using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals n. We can rewrite the power series as the following.
Find the integral int(e^(-y^2))dy
Final answer to the exercise
$\frac{1}{2}\sqrt{\pi }\mathrm{erf}\left(y\right)+C_0$