$\:\frac{x^3-8x+5}{x+3}$
$\left(\frac{1}{2}x+\frac{3}{4}\right)^3$
$\frac{x^2-5x+4}{x+1}$
$4\:x\:\left(-12\right)$
$-x^2+3x+2<0$
$121y^2+22yz+z^2$
$\left(-4\right)-\left(-5\right)+\left(-6\right)-\left(-1\right)+\left(-5\right)$
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