Exercise
$\int-\left(cos^6x-5cos^2x-cosx\right)\left(sinx\right)dx$
Step-by-step Solution
Learn how to solve problems step by step online. Solve the trigonometric integral int(-(cos(x)^6-5cos(x)^2-cos(x))sin(x))dx. The integral of a function times a constant (-1) is equal to the constant times the integral of the function. Rewrite the integrand \sin\left(x\right)\left(\cos\left(x\right)^6-5\cos\left(x\right)^2-\cos\left(x\right)\right) in expanded form. Expand the integral \int\left(\cos\left(x\right)^6\sin\left(x\right)-5\cos\left(x\right)^2\sin\left(x\right)+\frac{-\sin\left(2x\right)}{2}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral -\int\cos\left(x\right)^6\sin\left(x\right)dx results in: \frac{\cos\left(x\right)^{7}}{7}.
Solve the trigonometric integral int(-(cos(x)^6-5cos(x)^2-cos(x))sin(x))dx
Final answer to the exercise
$\frac{\cos\left(x\right)^{7}}{7}-\frac{5}{3}\cos\left(x\right)^{3}-\frac{1}{4}\cos\left(2x\right)+C_0$