$\left(\frac{\left(4x^3-6x\right)}{\left(-6\right)}\right)^3$
$-2b\cdot\frac{4b^{12}}{25}$
$-\left\{-25+10-\left(-32+10\right)-54-11\right\}$
$7x^2-4x+1\ge0$
$-6m^2+4mn$
$\int4x\left(\sqrt{2x+7}\right)dx$
$9^{4}\cdot10^{4}$
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