Exercise
$\int6x\sqrt{3x^2+1}dx$
Step-by-step Solution
Learn how to solve integration by trigonometric substitution problems step by step online. Integrate int(6x(3x^2+1)^(1/2))dx. The integral of a function times a constant (6) is equal to the constant times the integral of the function. First, factor the terms inside the radical by 3 for an easier handling. Taking the constant out of the radical. We can solve the integral 6\int\sqrt{3}x\sqrt{x^2+\frac{1}{3}}dx by applying integration method of trigonometric substitution using the substitution.
Integrate int(6x(3x^2+1)^(1/2))dx
Final answer to the exercise
$\frac{2}{3}\sqrt{\left(3x^2+1\right)^{3}}+C_0$