5x+20=−55x+20=-55x+20=−5
(2x2y)−1(−2x2y3)2\frac{\left(2x^2y\right)^{-1}}{\left(-2x^2y^3\right)^2}(−2x2y3)2(2x2y)−1
−11.034−8.848-11.034-8.848−11.034−8.848
−.002=ln(.001x+.05)-.002=\ln\left(.001x+.05\right)−.002=ln(.001x+.05)
∫2ln (x)x2dx\int\frac{2\ln\:\left(x\right)}{x^2}dx∫x22ln(x)dx
limx→−π4(2sin(x)cos(x))\lim_{x\to-\frac{\pi}{4}}\left(2\sin\left(x\right)\cos\left(x\right)\right)x→−4πlim(2sin(x)cos(x))
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