$\frac{2x^3-4x^2-2x+3}{-3}$
$\lim_{x\to2}\frac{ln\left(2x-3\right)}{x^3-4}$
$x^3+x^2-14x+6.x-3$
$\int_{\frac{-\pi}{4}}^{\frac{\pi}{2}}\left(\sin\left(3x\right)\right)dx$
$4\cdot\left(5\right)\cdot\left(-10\right)$
$6x-8>3x-1$
$\frac{x^2-6x+4}{x-1}$
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