Integrate int(8x-4)dx

 Exercise

$\int8x-4dx$

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Expand the integral $\int\left(8x-4\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$\int8xdx+\int-4dx$

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The integral $\int8xdx$ results in: $4x^2$

$4x^2$

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The integral $\int-4dx$ results in: $-4x$

$-4x$

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Gather the results of all integrals

$4x^2-4x$

 

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$4x^2-4x+C_0$

$4x^2-4x+C_0$

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