$y'=\sqrt{yx},\:y\left(1\right)=2$
$7-3\cdot2+6$
$\cos^2x-\cos x=2$
$m^2+12m+36=0$
$\int\frac{\sqrt{x^2-324}}{x}dx$
$=\left(-6\right)^2-\left(-3\right)^2-4$
$12^5y^2+9x^4y+6x^3y^2$
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