Exercise
$\int_0^{\infty}\left(\frac{x-3}{x^2+4x+3}\right)dx$
Step-by-step Solution
Learn how to solve special products problems step by step online. Integrate the function (x-3)/(x^2+4x+3) from 0 to infinity. Rewrite the expression \frac{x-3}{x^2+4x+3} inside the integral in factored form. Rewrite the fraction \frac{x-3}{\left(x+1\right)\left(x+3\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{-2}{x+1}+\frac{3}{x+3}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{-2}{x+1}dx results in: -2\ln\left(x+1\right).
Integrate the function (x-3)/(x^2+4x+3) from 0 to infinity
Final answer to the exercise
The integral diverges.