Since the integral $\int_{1}^{3}\frac{1}{\sqrt{x-2}}dx$ has a discontinuity inside the interval, we have to split it in two integrals
The integral $\int_{1}^{2}\frac{1}{\sqrt{x-2}}dx$ results in: $-2\sqrt{-1}$
The integral $\int_{2}^{3}\frac{1}{\sqrt{x-2}}dx$ results in: $2$
Gather the results of all integrals
Calculate the power $\sqrt{-1}$ using complex numbers
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