Exercise
$\int_2^{-2}\left(3y^2+4y+6\right)dy$
Step-by-step Solution
Learn how to solve problems step by step online. Integrate the function 3y^2+4y+6 from 2 to -2. Simplify the expression. The integral of a constant is equal to the constant times the integral's variable. Apply the power rule for integration, \displaystyle\int x^n dx=\frac{x^{n+1}}{n+1}, where n represents a number or constant function, such as 2. Simplify the fraction -3\left(\frac{y^{3}}{3}\right).
Integrate the function 3y^2+4y+6 from 2 to -2
Final answer to the exercise
$-37$