Exercise
$\int_2^3\sin6x^32x^2dx$
Step-by-step Solution
Final answer to the exercise
$2\left(\left(3^2\cdot -\frac{1}{6}\cos\left(6\cdot 3\right)+3\left(\frac{1}{18}\right)\sin\left(6\cdot 3\right)+\frac{1}{108}\cos\left(6\cdot 3\right)\right)\frac{3}{4}+\frac{1}{72}\cos\left(18\cdot 3\right)\cdot 3^2+3-\frac{1}{648}\sin\left(18\cdot 3\right)-\frac{1}{11664}\cos\left(18\cdot 3\right)-\left(\left(2^2\cdot -\frac{1}{6}\cos\left(6\cdot 2\right)+2\left(\frac{1}{18}\right)\sin\left(6\cdot 2\right)+\frac{1}{108}\cos\left(6\cdot 2\right)\right)\frac{3}{4}+\frac{1}{72}\cos\left(18\cdot 2\right)\cdot 2^2+2-\frac{1}{648}\sin\left(18\cdot 2\right)-\frac{1}{11664}\cos\left(18\cdot 2\right)\right)\right)$