Exercise
$\int_2^42\pi.x^2\sqrt{1+4x^2}dx$
Step-by-step Solution
Final answer to the exercise
$6.2831853\left(4\frac{1}{16}\sqrt{\left(1+4\cdot 4^2\right)^{3}}+4\frac{3}{32}\sqrt{1+4\cdot 4^2}+\frac{3}{64}\ln\left|\sqrt{1+4\cdot 4^2}+2\cdot 4\right|+4\left(-\frac{1}{8}\right)\sqrt{1+4\cdot 4^2}-\frac{1}{16}\ln\left|\sqrt{1+4\cdot 4^2}+2\cdot 4\right|-\left(2\frac{1}{16}\sqrt{\left(1+4\cdot 2^2\right)^{3}}+2\frac{3}{32}\sqrt{1+4\cdot 2^2}+\frac{3}{64}\ln\left|\sqrt{1+4\cdot 2^2}+2\cdot 2\right|+2\left(-\frac{1}{8}\right)\sqrt{1+4\cdot 2^2}-\frac{1}{16}\ln\left|\sqrt{1+4\cdot 2^2}+2\cdot 2\right|\right)\right)$