$2^3.5^3.7^3$
$\frac{1}{2}-\frac{1}{2}$
$-15\cdot7$
$4\sin^2x-5\sin x+1=0$
$15-12+x-9-2x$
$-13-\left(-16\right)+\left(9\right)\left(-10\right)-25$
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