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Solving: $\csc\left(y\right)\left(2y-\cos\left(2y=\cot\left(2y\cos\left(2y\right)\right)\right)\right)$
Solve instead: $\left(\csc\left(2y-\cos\left(2y=\cot\left(2y\cdot\cos\left(2y\right)\right)\right)\right)\right)$

Exercise

$\left(\csc\left(2y-\cos\left(2y=\cot\left(2y\cdot\cos\left(2y\right)\right)\right)\right)\right)$

Step-by-step Solution

1

Multiply the single term $\csc\left(y\right)$ by each term of the polynomial $\left(2y-\cos\left(2y=\cot\left(2y\cos\left(2y\right)\right)\right)\right)$

$2y\csc\left(y\right)-\cos\left(2y=\cot\left(2y\cos\left(2y\right)\right)\right)\csc\left(y\right)$

Final answer to the exercise

$2y\csc\left(y\right)-\cos\left(2y=\cot\left(2y\cos\left(2y\right)\right)\right)\csc\left(y\right)$

Try other ways to solve this exercise

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Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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