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Exercise

$\left(\frac{\left(20m^2n-mn\right)}{9x^2-30xy+25y^2}\right)\left(\frac{n^2+n}{m^2-n^2}\right)$

Step-by-step Solution

1

Multiplying fractions $\frac{20m^2n-mn}{9x^2-30xy+25y^2} \times \frac{n^2+n}{m^2-n^2}$

$\frac{\left(20m^2n-mn\right)\left(n^2+n\right)}{\left(9x^2-30xy+25y^2\right)\left(m^2-n^2\right)}$

Final answer to the exercise

$\frac{\left(20m^2n-mn\right)\left(n^2+n\right)}{\left(9x^2-30xy+25y^2\right)\left(m^2-n^2\right)}$

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Main Topic: Integrals of Rational Functions

Integrals of rational functions of the form R(x) = P(x)/Q(x).

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