$\left(\frac{1}{2}x^3m^2+3\right)\left(4x^3m^2-1\right)$
$t^3\sqrt{t}^4-1\:$
$1776.241633-8\cdot\frac{14\sqrt{7}-10\sqrt{5}}{3}$
$\frac{d}{dx}\left(7x\sqrt{x}+\frac{\left(4\right)}{x^2\sqrt{x}}\right)$
$\left\{\sqrt{27\left[\left(\sqrt{12}-\sqrt{3}\right)\left(\sqrt{45-\sqrt{20}}\right)\right]-\sqrt{80}}\right\}$
$\left(+2\right)-\left(-2\right)$
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