$x^3+2x^2+1x-8$
$8x^2+4\le12$
$\frac{d}{dx}\left(y=cos\left(\sin\left(tan\left(x^2\right)\right)\right)\right)$
$\left(x^2+3y\right)^3$
$3x^2=5+2x$
$tan\:x\:=\:\left(-\frac{5}{12}\right)$
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