$\frac{dy}{dx}=\frac{\left(4y^2\right)}{x}$
$\frac{d^2}{dx^2}\left(x^3-2x\right)^2$
$\left(2x^2\right)\left(5y^3\right)$
$2y+14=28$
$\int\:\frac{x^2-5x+16}{\left(2x+1\right)\left(x-2\right)^2}\:dx$
$4-5-6+2-2+3-7$
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