Exercise
$\left(\frac{1}{7}y^{2t+1}-\frac{1}{4}y^{t+2}\right)^2$
Step-by-step Solution
Learn how to solve special products problems step by step online. Expand the expression (1/7y^(2t+1)-1/4y^(t+2))^2. Expand \left(\frac{1}{7}y^{\left(2t+1\right)}-\frac{1}{4}y^{\left(t+2\right)}\right)^2. When multiplying exponents with same base we can add the exponents. Combining like terms 2t and t. The power of a product is equal to the product of it's factors raised to the same power.
Expand the expression (1/7y^(2t+1)-1/4y^(t+2))^2
Final answer to the exercise
$\frac{1}{49}y^{\left(4t+2\right)}-\frac{1}{14}y^{\left(3t+3\right)}+\left(-\frac{1}{4}y^{\left(t+2\right)}\right)^2$