$\left(3x^2+y^9\right)dx+\left(9xy^8\right)dy=0$
$\left(3x^2-4x+9\right)\cdot\left(x^5+10\right)$
$\int e^{2x+3}dx$
$x+5=2x-4$
$\frac{\cot^2\left(25\right)}{\tan^2\left(65\right)}-\csc^2\left(65\right)$
$\int\frac{1}{\sqrt{3+4x-x^2}}dx$
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