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Exercise

(59−0.25∞)⋅(16−0.103∞)\left(\frac{5}{9}-0.25\infty\right)\cdot\left(\frac{1}{6}-0.103\infty\right)

Step-by-step Solution

1

Any expression multiplied by infinity tends to infinity, in other words: ∞⋅(±n)=±∞\infty\cdot(\pm n)=\pm\infty, if n≠0n\neq0

(59−∞)⋅(16−0.103⋅∞)\left(\frac{5}{9}- \infty \right)\cdot \left(\frac{1}{6}-0.103\cdot \infty \right)
2

Any expression multiplied by infinity tends to infinity, in other words: ∞⋅(±n)=±∞\infty\cdot(\pm n)=\pm\infty, if n≠0n\neq0

(59−∞)⋅(16−∞)\left(\frac{5}{9}- \infty \right)\cdot \left(\frac{1}{6}- \infty \right)
3

Infinity plus any algebraic expression is equal to infinity

−−∞⋅∞- - \infty \cdot \infty
4

Multiply −1-1 times −1-1

∞⋅∞\infty \cdot \infty
5

If you multiply a very large number by another very large number, you get an even bigger number, so infinity times infinity equals infinity: ∞⋅∞=∞\infty\cdot\infty=\infty

∞\infty

Final answer to the exercise

∞\infty

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Similar Questions Solved

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−∞−∞-\infty-\infty

Main Topic: Operations with Infinity

Indications for how we should operate with infinity. Very useful to solve limits.

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(59 −0.25∞)·(16 −0.103∞)
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