$3xy^2+5y-y^3$
$2\sec^2x-8\tan\:x=-4$
$y^{12}\cdot y^9$
$\left(\frac{1}{3}x^3+4y^2\right)^2$
$7\left(9x\right)+6x$
$3\:\sin u\:-\:\cos^2\:u\:-\:3\:=0$
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