d2dx2(x3+7x)\frac{d^2}{dx^2}\left(\frac{x^3+7}{x}\right)dx2d2(xx3+7)
(5x+111)(5x−111)\left(5x+\frac{1}{11}\right)\left(5x-\frac{1}{11}\right)(5x+111)(5x−111)
(16a5)(−3a2)(4a7)\left(\frac{1}{6}a^5\right)\left(-3a^2\right)\left(4a^7\right)(61a5)(−3a2)(4a7)
∫1(u2+1)(u−1)du\int\frac{1}{\left(u^2+1\right)\left(u-1\right)}du∫(u2+1)(u−1)1du
(x3 − 4)2\:\left(x^3\:-\:4\right)^2(x3−4)2
2x4−16xy32x^4-16xy^32x4−16xy3
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