$\left|\left(2abc^3+1\right)-8\right|^2$
$\frac{dy}{dx}=\frac{y\cos x}{1+2y^{2}}$
$2\cos\left(x\right)\sin\left(x\right)+\sin\left(x\right)$
$3z^2=108$
$\frac{9x^2+6x+1}{3x+1}$
$\sin\left(45+a\right)-\cos\left(a-45\right)$
$-6+9+3-6+4-1+5-3+6$
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